+0  
 
0
1
1
avatar+1748 

A speech class has $4$ freshmen and $3$ sophomores. (Everyone is distinguishable.) In how many ways can they stand in line, so that all of the freshmen are standing next to each other?

 May 23, 2024

Best Answer 

 #1
avatar+806 
0

The freshmen are able to stand in 4! = 24 ways. There are 4 ways we can put them into the line with them all standing together. 

The sohphomores can staned in 3! = 6. 

 

We just have to do 24*4*6 = 576. 

 

There are 576 ways we could arrange them!

 

Thanks! :)

 May 23, 2024
 #1
avatar+806 
0
Best Answer

The freshmen are able to stand in 4! = 24 ways. There are 4 ways we can put them into the line with them all standing together. 

The sohphomores can staned in 3! = 6. 

 

We just have to do 24*4*6 = 576. 

 

There are 576 ways we could arrange them!

 

Thanks! :)

NotThatSmart May 23, 2024

5 Online Users

avatar
avatar
avatar
avatar
avatar