A speech class has $4$ freshmen and $3$ sophomores. (Everyone is distinguishable.) In how many ways can they stand in line, so that all of the freshmen are standing next to each other?

LiIIiam0216 May 23, 2024

#1**0 **

The freshmen are able to stand in 4! = 24 ways. There are 4 ways we can put them into the line with them all standing together.

The sohphomores can staned in 3! = 6.

We just have to do 24*4*6 = 576.

There are 576 ways we could arrange them!

Thanks! :)

NotThatSmart May 23, 2024

#1**0 **

Best Answer

The freshmen are able to stand in 4! = 24 ways. There are 4 ways we can put them into the line with them all standing together.

The sohphomores can staned in 3! = 6.

We just have to do 24*4*6 = 576.

There are 576 ways we could arrange them!

Thanks! :)

NotThatSmart May 23, 2024