+2115 A speech class has $4$ freshmen and $3$ sophomores. (Everyone is distinguishable.) In how many ways can they stand in line, so that all of the freshmen are standing next to each other?
+1365 The freshmen are able to stand in 4! = 24 ways. There are 4 ways we can put them into the line with them all standing together.
The sohphomores can staned in 3! = 6.
We just have to do 24*4*6 = 576.
There are 576 ways we could arrange them!
Thanks! :)
+1365 The freshmen are able to stand in 4! = 24 ways. There are 4 ways we can put them into the line with them all standing together.
The sohphomores can staned in 3! = 6.
We just have to do 24*4*6 = 576.
There are 576 ways we could arrange them!
Thanks! :)
