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The entries in a certain row of Pascal's triangle are
1, n, \dots, n, 1.
The average of the entries in this row is 2. Find $n$.

 May 10, 2024
 #1
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1. The row in Pascal's triangle has entries 1, n, ..., n, 1 with an average of 2.
 

2. The sum of entries in the row is calculated as 2n.

 

3. In Pascal's triangle, each entry is the sum of the two entries above it in the previous row.

 

4. The equation 2n = 2^(n-1) is solved to find the value of n.

 

5. The value of n in the row of Pascal's triangle is determined to be 2.

 May 11, 2024

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