In how many ways can 4 balls be placed in boxes if the balls are indistinguishable, and the boxes are distinguishable?
+195 Let's consider each box as a separate event.
For the first ball, there are four boxes to choose from.
For the second ball, there are four boxes to choose from.
For the third ball, there are four boxes to choose from.
For the fourth ball, there are four boxes to choose from.
Since the balls are indistinguishable, the order in which we place them in the boxes does not matter.
Therefore, the total number of ways to place the four balls in the boxes is:
4 x 4 x 4 x 4 = 256
So there are 256 ways to place 4 indistinguishable balls in distinguishable boxes.
