+2653 Four children and four adults are to be seated at a circular table. In how many different ways can they be seated if all the children are together? (Two seatings are considered the same if one can be rotated to form the other.)
+1908 We would just have \(3!*4! = 6*24= 144\) ways, since we must place a children down before completing the problem.
Thanks! :)
