+956 A nursery determines the demand in May for potted plants in p=3 - (x/1000). The cost of growing x plant is C(x) = 0.02x+400, 0≤ x ≤ 6000. Determine the marginal profit function.
a) 2.98x - (x^2/1000)
b) 2.98 - (x/500)
c) 2.98x - (x^2/1000) + 400
d) 2.98 + (x/500)
+349 Marginal Profit = Marginal Revenue - Marginal Cost
Marginal Cost = C'(x) = 0.02
Revenue = No. of Items sold * Price = x * (3 - (x/1000)) = \(-{x^2\over1000}+3x\)
Marginal Revenue = R'(x) = \(-{x\over500}+3\)
Marginal Profit = \(-{x\over500}+3-0.02\) = \(2.98-{x\over500}\)
The answer is letter B 
