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# @CPhill - ASAP

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A nursery determines the demand in May for potted plants in p=3 - (x/1000). The cost of growing x plant is C(x) = 0.02x+400, 0≤ x ≤ 6000. Determine the marginal profit function.

a) 2.98x - (x^2/1000)

b) 2.98 - (x/500)

c) 2.98x - (x^2/1000) + 400

d) 2.98 + (x/500)

Mar 30, 2018

### 3+0 Answers

#1
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Sorry, Julius...I don't know this one...!!!   Mar 30, 2018
#2
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Marginal Profit = Marginal Revenue - Marginal Cost

Marginal Cost = C'(x) = 0.02

Revenue = No. of Items sold * Price = x * (3 -  (x/1000)) = $$-{x^2\over1000}+3x$$

Marginal Revenue = R'(x) = $$-{x\over500}+3$$

Marginal Profit = $$-{x\over500}+3-0.02$$ = $$2.98-{x\over500}$$

The answer is letter B Mar 31, 2018
#3
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Thanks, Mathhemathh!!!....great answer  !!!   CPhill  Mar 31, 2018