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There is a total of 27 quarters stacked in four piles. The first pile has 5 fewer than the second pile. The second pile has 4 more than the third pile. The fourth pile has three times as many as the second pile. How many quarters are in the fourth pile?

 Dec 25, 2020
 #1
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Hmmmm....WHY is this posted THREE times !????

 Dec 26, 2020
 #3
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IDK OK

Guest Dec 26, 2020
 #2
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[Q + Q + 4 + Q - 1 +3Q + 12]=27, solve for Q


Q = 2 - Third pile


2 + 4 = 6 - Second pile


2 - 1 = 1 - First pile


6 * 3 = 18 - Forth pile

 

[2 + 6 + 1 + 18]==27 Quarters.

 Dec 26, 2020
 #4
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THANKS SO MUCH!!!

Guest Dec 26, 2020
 #5
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Let  the second pile  contain  N quarters

 

Let  the first contain N - 5

 

Let the third contain N - 4

 

Let the fourth contain 3N

 

So

 

(N  - 5)  + N +  ( N - 4)  + 3N   =27   simplify

 

6N - 9  =  27       add 9 to both sides

 

6N   = 36       divide both sides  by 6

 

N =  6

 

The fourth contains  3 * 6     =  18

 

 

cool cool cool

 Dec 26, 2020

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