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if person A eats 1/3 of there crackers, and person b eats 1/4 of the same plate and the left over amount of crackers is 5. how many crackers are there to begin

Guest Mar 24, 2017
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3+0 Answers

 #1
avatar+6900 
+2

Let x be the number of crackers originally.

\((1-\frac{1}{4})(1-\frac{1}{3})x=5\\ \dfrac{1}{2}x = 5\\ x = 10\)

There are 10 crackers originally and no cookies :(

 

Why no cookies I love cookies and I am a cookie :(

 

~The smartest cookie in the world.

PS: Cookies can type!!

MaxWong  Mar 24, 2017
 #2
avatar+95 
+2

I AGREE WITH MAX WONG THE AMOUNT OF CRACKERS WOULD BE 10

SISTERCOUSIN6969  Mar 24, 2017
 #3
avatar+79843 
+1

Let N be the number of crackers that we started with.....

 

If A eats (1/3)  of this there are   (2/3)N left

 

And B  eats  (1/4)  of this......so the amount left can be expressed as

 

[(2/3)N ] * (3/4)  = 5

 

[6/12] N = 5

 

[ 1/2] N  = 5      multiply both sides by 2

 

N  = 10      and this is the number  we started with

 

 

 

cool cool cool

CPhill  Mar 24, 2017

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