if person A eats 1/3 of there crackers, and person b eats 1/4 of the same plate and the left over amount of crackers is 5. how many crackers are there to begin
+9673 Let x be the number of crackers originally.
\((1-\frac{1}{4})(1-\frac{1}{3})x=5\\ \dfrac{1}{2}x = 5\\ x = 10\)
There are 10 crackers originally and no cookies :(
Why no cookies I love cookies and I am a cookie :(
~The smartest cookie in the world.
PS: Cookies can type!!
+129850 Let N be the number of crackers that we started with.....
If A eats (1/3) of this there are (2/3)N left
And B eats (1/4) of this......so the amount left can be expressed as
[(2/3)N ] * (3/4) = 5
[6/12] N = 5
[ 1/2] N = 5 multiply both sides by 2
N = 10 and this is the number we started with
