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# Crackers

+2
204
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if person A eats 1/3 of there crackers, and person b eats 1/4 of the same plate and the left over amount of crackers is 5. how many crackers are there to begin

Guest Mar 24, 2017
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#1
+6928
+2

Let x be the number of crackers originally.

$$(1-\frac{1}{4})(1-\frac{1}{3})x=5\\ \dfrac{1}{2}x = 5\\ x = 10$$

There are 10 crackers originally and no cookies :(

~The smartest cookie in the world.

MaxWong  Mar 24, 2017
#2
+95
+2

I AGREE WITH MAX WONG THE AMOUNT OF CRACKERS WOULD BE 10

SISTERCOUSIN6969  Mar 24, 2017
#3
+82839
+1

Let N be the number of crackers that we started with.....

If A eats (1/3)  of this there are   (2/3)N left

And B  eats  (1/4)  of this......so the amount left can be expressed as

[(2/3)N ] * (3/4)  = 5

[6/12] N = 5

[ 1/2] N  = 5      multiply both sides by 2

N  = 10      and this is the number  we started with

CPhill  Mar 24, 2017

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