if person A eats 1/3 of there crackers, and person b eats 1/4 of the same plate and the left over amount of crackers is 5. how many crackers are there to begin

Guest Mar 24, 2017

#1**+2 **

Let x be the number of crackers originally.

\((1-\frac{1}{4})(1-\frac{1}{3})x=5\\ \dfrac{1}{2}x = 5\\ x = 10\)

There are 10 crackers originally and no cookies :(

Why no cookies I love cookies and I am a cookie :(

~The smartest cookie in the world.

PS: Cookies can type!!

MaxWong
Mar 24, 2017

#3**+1 **

Let N be the number of crackers that we started with.....

If A eats (1/3) of this there are (2/3)N left

And B eats (1/4) of this......so the amount left can be expressed as

[(2/3)N ] * (3/4) = 5

[6/12] N = 5

[ 1/2] N = 5 multiply both sides by 2

N = 10 and this is the number we started with

CPhill
Mar 24, 2017