culture starts with 10000 bacteria, and the number doubles every 40 minutes.
a. Find a function that models the number of bacteria at time t.
b. Find the number of bacterial after one hour.
c. After how many minutes will there be (50000 +m) bacteria? m=8
d. Sketch a graph of the number of bacterial at time t.
please help me
a) let t be the number of bacteria as its instructing you, A be the starting point, r be the rate of increment and T be time.
lets use the formula t=A\times r^T
T itself can be broken down into 2 components -- the 40 minutes were stated, and another unknown value which would be the time you want it to be; so: $ t=\frac{T_m}{40} $
respectively, substitute the values in:
$ t=1000\times 2^{\frac{T_m}{40}} $
b) we are working in minutes so one hour is equal to 60 minutes ; just plug that as T_m
$ t=1000\times 2^{\frac{60}{40}} $
$t\approx 1000\times 2.828 $
$t\approx 2828 $
c) its stated that $ t=(50000 +m)$ where $m=8$
$(50000 +8)=1000\times 2^{\frac{T_m}{40}} $ thus,
$50008=1000\times 2^{\frac{T_m}{40}}$
get rid of the base
$ 2^{\frac{T_m}{40}}=\frac{6251}{125} $
$ \frac{T_m}{40}\ln \left(2\right)=\ln \left(\frac{6251}{125}\right) $
$ T_m=225.7 $
d) use desmos, or try manually graphing it.
a. N = 10000 ( 2)^(t/40) where N is the number of bacteria after t minutes
b. N = 10000 (2)^(60/40) ≈ 28284
c. 5000 + 8 = 10000 (2)^(t/40)
50008 = 10000 (2) ^(t/40)
50008 /10000 = 2^(t/40) take the log of each side
log (50008 / 10000) = log 2^(t/40) and we can write
log (50008 / 10000) = (t/40) log (2)
t = 40 log ( 50008 / 10000) / log (2) ≈ 92.9 minutes
d. Here's the graph ( subbing y for N and x for t)
https://www.desmos.com/calculator/t5egnmgcks