+0

# /gone

-2
144
4
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Dec 15, 2019
edited by whoisjoe  Jan 7, 2020

#1
+88
+2

Since we know it is a cyclic quad, Angle A + Angle C is 180.

So we can plug in angle A as 180- angle C.

(180-angleC)/2  is equal to angleC/4

3 angle C is 360.

Angle C is 120. So Angle A is 180-120 or 60.

Now Angle B is 30*3 or 90. So Angle D is 180-90 or 90.

The largest angle out of all of these are angle C or 120.

Hope this helps.

~~GF

Dec 15, 2019
#2
+109750
+1

∠A            ∠C

___  =     ____       wihich implies  that

2             4

4∠A  = 2∠C       which implies that

2∠A    =  ∠C

But  ∠A  + ∠C   are supplementary......so....

∠A + 2∠A  = 180°

3∠A  = 180°

∠A  =60°

So  ∠C = 2∠A  =  2(60)  =120°

Further we have that

∠B           ∠C           120

___  =     ____  =   ____   =   30

3              4             4

So

∠B

___  =   30

3

∠B  = 90

And   ∠B  + ∠D   are supplementary

So

∠B   + ∠D   = 180

90  + ∠D  = 180

∠D  =90°

So  C is the largest angle  = 120°

Dec 15, 2019
#3
+30
0

Thanks to both goreisthebest and CphIll!

Dec 15, 2019
#4
+109750
0

THX, whoisjoe.....!!!!

CPhill  Dec 15, 2019