+64 an experiment consists of picking a card from a standard deck of playing cards and drawing a counter from a bag that contains 5 counters: 2 blue, 2 white, 1 red.
A) picking a spade and drawing a blue counter
B) picking a red card and drawing a red counter
C) picking a face card and not drawing a white counter
D) picking a diamond and drawing a green counter
+129899 A) picking a spade and drawing a blue counter
P(spade) = 1/4 ... P(blue) = 2/5
So P(spade) and P(blue) = 1/4 * 2/5 = 2/20 = 1/10
B) picking a red card and drawing a red counter
P(red card) = 1/2 .... P(red counter) = 1/5
So.... P(red card) and P(red counter) = 1/2 * 1/5 = 1/10
C) picking a face card and not drawing a white counter
P(face card) = 12/52 = 3/13 ..... P(not white) = 3/5
So.. P(face card) * P(not white) = 3/13 * 3/5 = 9 / 65
D) picking a diamond and drawing a green counter
P(diamond) = 1/4 ... P(green) = 0/5 = 0
So P(diamond) * P(green) = (1/4) * 0 = 0
+5265 A: Spades are one of the 4 suits in the 52 card deck that is standard
13/52
Multiply by the blue counters over the total counters.
13/52 * 2/5 = 26/260 OR 1/10
1/10 chance of choosing a spade and a blue counter.
B: Red cards are half of the deck
1/2
Multiply by red counter over total
1/2*1/5= 1/10
1/10 chance of choosing a red card and red counter
C: Face cards are Jack, Queen, King. There are 12 in a standard deck
12/52
NOT choosing white means taking blue and red over the total counters
3/5
Multiply
12/52 * 3/5 = 36/260 OR 9/65
9/65 chance of choosing a face card and not choosing a white counter
D: Diamonds make up 1/4 of the deck
1/4
There are no green counters
Probability of choosing a diamond AND a green counter is 0.
