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each time parker shoots a free throw in basketball, he has an 80% chance of making the shot. Soppose he is give 3 free throws. find the probability of each event.

A)  Makes the basket, misses the basket, Makes the basket

 


B) Makes all 3 shots

 

C) Misses all 3 shots

 

 

D) Misses the frist two and makes the third

 

 

 

smiley

cheifraidhunter  Jun 8, 2017
 #1
avatar+88775 
+2

 

A)  Makes the basket, misses the basket, Makes the basket

 

(.80) (.20) (.80)  =  (.80)^2 (.20)  = 0.128  =  12.8 %

 

 

B) Makes all 3 shots

 

(.80)^3    =  0.512  =  51.2 %

 

 

C) Misses all 3 shots

 

(.20)^3  =  0.008  =  .8 %

 

 

 

D) Misses the frist two and makes the third

 

(.20)^2 (.80)  =  0.032  =  3.2 %

 

 

cool cool cool

CPhill  Jun 8, 2017

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