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Transmission time of 1 TB of data at 1.5 Mbps?
 Jan 29, 2014
 #1
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1 TB = 1048576 MB @ 1.5 MB/s = 1048576/1.5 = 699050.666667 seconds = 8.1 days
 Jan 29, 2014
 #2
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Zamarronics:

1 TB = 1048576 MB @ 1.5 MB/s = 1048576/1.5 = 699050.666667 seconds = 8.1 days



Hey Zamarronics, how do you get to 1048576 MB in 1 TB?
Unless there is some computer round off I am unaware about,tera literally means the fourth power of 1000 or 10 12 bytes.

Therefore I'd say that 1TB = 1000000 MB @ 1.5 MB/s = 6666666 2/3 seconds = 7.7 days
 Jan 29, 2014
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Postby Guest » Tue Jan 28, 2014 7:48 pm
Transmission time of 1 TB of data at 1.5 Mbps?
***

To properly calculate this, a clarification is necessary.
(The most glaring error is converting bits to bytes)

In the early years of computing, there was no significant error in using the same prefix for either quantity (2^10 = 1024 and 10^3 = 1000 they are about equal, to two significant figures). Thus, the SI prefixes were utilized indicate nearby binary multiples for these computer-related quantities.
-- This is actually referenced in the preamble to the amendments for IEEE. (You'll have to search for it in the original documents, or search for it on Wiki - a much easier read). As computer power increased and memory and disk size increased the error became significant.

This along with inconsistent use of the symbols to indicate quantities for and definitions of bits and bytes (for example: the unit symbol "Mb", has been widely used for both megabytes and megabits), the clarification of current symbols and the introduction of new symbols for measurement became an imperative.

To unambiguously represent these quantities and unit symbols, the IEEE 1541 sets new recommendations

(Note: IEEE and IEC are not the same entity).

The formality started in 1998 an when amendment was proposed to clarify data and data rates. The amendment was adopted in 1999 by the
International Electrotechnical Commission (IEC) published as Amendment 2 to "IEC 60027-2.

In 2002, a proposal (IEEE 1541-2002) was introduced to explicitly define symbols and value units . This was elevated to a full-use standard by the IEEE Standards Association in 2005, and reaffirmed on 27 March 2008. These standards, among others, included the following:

The upper case "B" is a byte

The lower case "b" is a "bit" and 8 (eight) bits are a "Byte"

The upper case "K" when referring to a binary value is 2^10 = 1024. (Always was and always will be).

"M" is a Million (10^6). (This is a decimal number its use is common in older documents where
Meg was often defined as 1000*1024, but sometimes as 1000000).

"Mi" is 2^20 = 1,048,576. (Mebi is Binary). The modern Meg.

"Gi" is 2^30 = 1,073,741,824 (Gibi is Binary). The modern Gig.

"Ti" 2^40 2^40 =1,099,511,627,776 ("Tibi" is Binary) .

Though these symbols and value units are explicitly defined and have been for 9 years or more, confusion still abounds --This is true even in high-end technical papers exposited by scientists and engineers on the cutting-edge of technology. (Many formal papers often preface the definitions to avoid ambiguity).

********
Now to the question.
Postby Guest » Tue Jan 28, 2014 7:48 pm
Transmission time of 1 TB of data at 1.5 Mbps?

Another preface is necessary here: In "dial-up modem days" (back when bear skins and stone knives were common) depending on the modem protocol (handshake) the "data" was usually 7 bits plus 1 bit for parity (even or odd), plus two bits for control (a start and stop bit). This gave a total through-put of ten bits per unit of data. (A unit of data is a byte). As error correction code was improved the parity bit was abandoned which doubled the unique data that could be transmitted.

The value given is 1.5Mbps this suggests an error correction of 32 bits (8 bytes) per block, where a block is multiple (n) of 1024 bytes. Depending on the protocol the code can self correct via an algorithm (if the errors are not too close together) else request to resend the data block. However the throughput averages 1.5Mbps (including data and error correction)

First convert the b(its) (Mbps - not Mibps) per second to B(ytes) per second. 1.5E6/8 = 187500 bytes per second.

In this case, simply divide 1E12 (TB not TeB) by 187500 B(ytes)/s. 1E12/1.87500E5 = 5,333,333 seconds to port this amount of data. This is 1481.5 hours or 61.7 days. If both are the Binary values it's 64.7 days

(Another note: Most "high-speed data providers give the download speed. The upload speed is about 1/4 this). A T1 type connection would be about 10 times as fast -- unless band width is heavy by other connected devices. Also the up-download speeds are about equal for T1's. There are other protocols which can increase through-put speed by a few percent.

This is my two-bits worth.
~~D~~
 Jan 30, 2014
 #4
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64.7269 Days



-----

1048576(MB/TB)*8(b/B) = MB/TB=>Mb/TB
---

Thanks David
 Feb 3, 2014

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