Find all values of a that satisfy the equation \(\frac{1}{a^3 + 7} -7 = \frac{-a^3}{a^3 + 7}.\)

I multiplied both sides by a^3+7 to get -6=-a^3.

I think a solution to a would be \(a=\sqrt[3]{6}\) but I'm not sure...

dolphinia Feb 12, 2022

#1**+2 **

That's a good step, but the problem with your reasoning is that -7 by itself doesn't have a^3 + 7 in the denominator, so you would have to convert -7 to (-7(a^3 + 7))/(a^3 + 7) before solving.

CubeyThePenguin Feb 12, 2022