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Find the largest number δ such that if |x − 3| < δ, then |4x − 12| < ε, where ε = 1

Repeat and determine δ with ε = 0.1.

 Sep 22, 2020
 #1
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Find the largest number δ such that if |x − 3| < δ, then |4x − 12| < ε, where ε = 1

Repeat and determine δ with ε = 0.1.

 

Hint:

 

Start by finding x in terms of  ε  

 

|4x − 12| < ε

 

then substitute that value of x into the first inequality and solve

Do not replace  ε with 1 until the end.

 

 

Have a go and if you want more help display, or talk about what you have done.

 Sep 22, 2020
edited by Melody  Sep 22, 2020

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