Find the largest number δ such that if |x − 3| < δ, then |4x − 12| < ε, where ε = 1
Repeat and determine δ with ε = 0.1.
Find the largest number δ such that if |x − 3| < δ, then |4x − 12| < ε, where ε = 1
Repeat and determine δ with ε = 0.1.
Hint:
Start by finding x in terms of ε
|4x − 12| < ε
then substitute that value of x into the first inequality and solve
Do not replace ε with 1 until the end.
Have a go and if you want more help display, or talk about what you have done.