derivative

Possible derivation:
d/dt(1 + 0.00003 t + 4.×10^-7 t^2)
Differentiate the sum term by term and factor out constants:
 = d/dt(1) + 0.00003 (d/dt(t)) + 4.×10^-7 (d/dt(t^2))
The derivative of 1 is zero:
 = 0.00003 (d/dt(t)) + 4.×10^-7 (d/dt(t^2)) + 0
Simplify the expression:
 = 0.00003 (d/dt(t)) + 4.×10^-7 (d/dt(t^2))
The derivative of t is 1:
 = 4.×10^-7 (d/dt(t^2)) + 1 0.00003
Use the power rule, d/dt(t^n) = n t^(n - 1), where n = 2: d/dt(t^2) = 2 t:
 = 0.00003 + 4.×10^-7 2 t
Simplify the expression:
Answer: |= 0.00003 + 8.×10^-7 t

Hi Helpls, welcome to our web2 forum :)

what is the derivative of 1+0.00003t+0.0000004t^2? with steps please

The derivative of 1 is 0

The derivative of  0.00003t

\(\frac{d}{dx}\;0.00003t^1\\ =1*0.00003t^{1-1}\\ =0.00003t^{0}\\ =0.00003*1\\ =0.00003\\\)

and

The derivative of  0.0000004t^2 is  

\(=2* 0.0000004t^{2-1}  \\ = 0.0000008t  \\\)

So

\(\frac{d}{dx}\;[1+0.00003t+0.0000004t^2] =0.00003+0.0000008t\\\)