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avatar+271 

Differentiate with respect to t.

y = a cos(t) + t^2 sin(t)

 Feb 22, 2019
 #1
avatar+203 
+1

yo what is a

 Feb 22, 2019
 #2
avatar+271 
+1

No clue.  That is all im given

Ruublrr  Feb 22, 2019
 #3
avatar+203 
+1

okay. 

 Feb 22, 2019
 #4
avatar+203 
+1

 tcos(t)+ 2t sin (t) - sin (t)

 Feb 22, 2019
 #5
avatar+98060 
+3

"a" just denotes some constant.....so

 

y = acos(t) + t^2sin (t)

 

y '  =  - a sin(t)   + 2t sin (t) + t^2 cos(t)  =   

 

(2t - a) sin (t) + t^2 cos (t)

 

 

cool cool cool

 Feb 22, 2019
edited by CPhill  Feb 22, 2019
 #6
avatar+271 
+1

Sorry for the late response but I understand now.  I didn't even see the product rule between t^2 and sin(t).

Ruublrr  Feb 25, 2019

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