Determine the complex number satisfying the equation 3z+4i¯z=1−8i
Um... I'm only in 7th grade so I just going to solve WITHOUT the complex conjugate and Zbar thingy just for the fun of it.
1. Sqaure both sides.
9z^2-4z^2=1+8
9z^2-4z^2=9
5z^2=9
z^2=9/5
z=√95
3z + 4iz' = 1 - 8i
3 (a + bi) + 4i(a - bi) = 1 - 8i
3a + 3bi + 4ai + 4b = 1 - 8i
3a+ 4b = 1 ⇒ 12a + 16b = 4
4a + 3b = - 8 ⇒ -12a - 9b = 24
7b = 28
b = 4 and 3a + 4(4) = 1 ⇒ 3a = - 15 ⇒ a = -5
So
z = -5 + 4i
Thank you