Determine where f is continuous:
1. f(x) = sin-1 (2x)
2. f(x) = (sqrt(arctanx)) / (x^2 - 9)
I used a graphing calculator for #1 and found the interval to be [-0.5, 0.5], but is there any way I can do this more algebraically without the use of my graphing calculator?
I don't know how to approach #2 at all...
Thanks so much!
+14903 Determine where f is continuous:
Hello Guest!
1. f(x) = sin-1 (2x)\(f(x)=sin^{-1}(2x)\)
f(x) is continuous if: \(\color{blue}x\in \mathbb R\ |\ x\notin \{n\cdot \pi /2\}.\)
2. \(f(x) = \sqrt{arctan\ x} / (x^2 - 9)\)
\(\sqrt{arctan\ x}/(x^2-9)\) is continuous if: \(\color{blue}x\in \mathbb R\ |\ 0\le x< \infty\ and\ x\ne 3.\)
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