+532 i have seen this before, i will show you.
also to everyone else who is confused about the operations, it is \(\frac{f(5 + h)-f(5)}{h}\), not something else.
now, we have to calculate the numerator. f(h+5) is 2+4h+20-h^2-10h-25, and f(5) is -3. now you have (-h^2-6h)/h for the whole fraction, so the answer is -h-6.
someone check my work pleez
and hope this helped!
+532 ok here is my check: f(6)-f(5) should equal 3 according to you,
according to me it should be -7.
plugging in f(6), it is 2+24-36 or -10, and f(5) is 2+20-25 or -3, so it is -7 and i am right.
hope this helped, and the answer is actually -h-6.
+118673 I'll check asad.
Evaluate and Simplify.
f(x) = 2 + 4x − x^2, f(5 + h) − f(5) / h
I got an answer but I am not sure if I am right or not. My answer was, "4 - h"
\(\frac{f(5+h)-f(5)}{h}\\ =\frac{[2+4(5+h)-(5+h)^2]-[2+20-25]}{h}\\ =\frac{[2+20+4h-(25+h^2+10h)]-[-3]}{h}\\ =\frac{2+20+4h-25-h^2-10h+3}{h}\\ =\frac{4h-h^2-10h}{h}\\ =\frac{-h^2-6h}{h}\\ =\frac{h(-h-6)}{h}\qquad \text{where } h>0\\ =-h-6\)
So Asad, you were correct. Good work!
