+0  
 
0
105
8
avatar+790 

for both of them i tried subbing in the x number and subbing it in the differemtiated version of both but none seem to work so i guess my method is completely wrong, please help

the answer for a should be 2/3 >0

answer for b should be 5/2 > 0

 Dec 17, 2018
edited by YEEEEEET  Dec 17, 2018
 #1
avatar+698 
0

I do not know how you define "increasing or decreasing", but I did graph both of the functions to help you here

 

I also think that the answers for (a) and (b) are supposed to be one of the words "increasing" or "decreasing". (hence, that is what the question asked for)

 

- PM

 Dec 17, 2018
 #3
avatar+790 
0

a and b should both be increasing and the numbers i showed are to explain why...

my question is how to get to those numbers...

YEEEEEET  Dec 17, 2018
edited by YEEEEEET  Dec 17, 2018
 #4
avatar+99331 
+2

 

 

\(f(x)=\frac{1}{3x^2}=\frac{1}{3}x^{-2}\\ f'(x) =\frac{-2}{3}x^{-3}\\ f'(-1) =\frac{-2}{3}\times (-1)^{-3}\\ f'(-1) =\frac{-2}{3*(-1)^{3}}\\ f'(-1)=\frac{-2}{3*-1}\\ f'(-1)=\frac{2}{3}\\ \)

Since the gradient at x=-1 is positive, the graph is increasing.

 

You can also see this from PM's graph. you can see that the gradient of the tangent to the curve is positive when x=-1

 Dec 17, 2018
edited by Melody  Dec 17, 2018
 #5
avatar+790 
+2

thank you very much

YEEEEEET  Dec 17, 2018
 #7
avatar+99331 
+2

You are very welcome. I will remember your good manners :)

Melody  Dec 17, 2018
 #6
avatar+99331 
+2

\(f(x)=4\sqrt{x}+\sqrt[4]{x}\\ f(x)=4*x^{0.5}+x^{0.25}\\ f'(x)=2x^{-0.5}+0.25x^{-0.75}\\ f'(16)=2*16^{-0.5}+0.25*16^{-0.75}\\ f'(16)=2*4^{-1}+0.25*16^{3/4*-1}\\ f'(16)=2*4^{-1}+0.25*2^{3*-1}\\ f'(16)=2*4^{-1}+0.25*8^{-1}\\ f'(16)=\frac{2}{4}+\frac{0.25}{8}\\ f'(16)=\frac{16}{32}+\frac{1}{32}\\ f'(16)=\frac{17}{32}\\ \)

 

The gradient for part b is NOT 5/2

 

However, it is positive so the curve is increasing.

 

I really did not need to do all that. As soon as the curve was differentiated it was clear that the for all positive values of x the curve would be increasing.   I mean the first derivative would be positive.

 Dec 17, 2018
edited by Melody  Dec 17, 2018
edited by Melody  Dec 17, 2018
 #8
avatar+790 
+1

oh... i kept on trying and couldnt seem to get to 5/2 LOL thanks for saving me from that endless loop

YEEEEEET  Dec 17, 2018

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