Points A, B, C, and T are in space such that each of \(\overline{TA}\), \(\overline{TB}\), and \(\overline{TC}\) is perpendicular to the other two. If TA = TB = 12 and TC = 6,then what is the distance from T to face ABC?

Any help is appreciated. Thanks a lot!

SuperMathGuy Aug 11, 2019

edited by
Guest
Aug 11, 2019

#1**+2 **

I have not worked this out

BUT

you can think of A,B and C being on an xyz space such that

A(12,0,0) B(0,0,12) and C(0,6,0)

and T os the origin (0,0,0)

Then I'd try doing what this video teaches.

Melody Aug 11, 2019

#2**+1 **

Thanks for the help, but I'm still having trouble solving for the answer. I don't really understand the video.

SuperMathGuy
Aug 11, 2019