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Points A, B, C, and T are in space such that each of \(\overline{TA}\)\(\overline{TB}\), and \(\overline{TC}\) is perpendicular to the other two. If TA = TB = 12 and TC = 6,then what is the distance from T to face ABC?

 

Any help is appreciated. Thanks a lot! 

 Aug 11, 2019
edited by Guest  Aug 11, 2019
 #1
avatar+103693 
+2

I have not  worked this out

BUT

you can think of A,B and C being on an xyz space such that 

A(12,0,0)    B(0,0,12)     and    C(0,6,0)

 

and T os the origin (0,0,0)

 

Then I'd try doing what this video teaches.

 

https://www.youtube.com/watch?v=0qYJfKG-3l8

 Aug 11, 2019
 #2
avatar+8 
+1

Thanks for the help, but I'm still having trouble solving for the answer. I don't really understand the video. 

SuperMathGuy  Aug 11, 2019
 #3
avatar+103122 
+2

Here : https://web2.0calc.com/questions/3d-geometry-please-help

 

 

cool cool cool

 Aug 12, 2019
 #4
avatar+103693 
0

Thanks Chris,

That addition should be helpful :)

Melody  Aug 13, 2019

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