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Points A, B, C, and T are in space such that each of $$\overline{TA}$$$$\overline{TB}$$, and $$\overline{TC}$$ is perpendicular to the other two. If TA = TB = 12 and TC = 6,then what is the distance from T to face ABC?

Any help is appreciated. Thanks a lot!

Aug 11, 2019
edited by Guest  Aug 11, 2019

#1
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I have not  worked this out

BUT

you can think of A,B and C being on an xyz space such that

A(12,0,0)    B(0,0,12)     and    C(0,6,0)

and T os the origin (0,0,0)

Then I'd try doing what this video teaches.

Aug 11, 2019
#2
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Thanks for the help, but I'm still having trouble solving for the answer. I don't really understand the video.

SuperMathGuy  Aug 11, 2019
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Aug 12, 2019
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Thanks Chris,