+8 Points A, B, C, and T are in space such that each of \(\overline{TA}\), \(\overline{TB}\), and \(\overline{TC}\) is perpendicular to the other two. If TA = TB = 12 and TC = 6,then what is the distance from T to face ABC?
Any help is appreciated. Thanks a lot!
+118689 I have not worked this out
BUT
you can think of A,B and C being on an xyz space such that
A(12,0,0) B(0,0,12) and C(0,6,0)
and T os the origin (0,0,0)
Then I'd try doing what this video teaches.
+8 Thanks for the help, but I'm still having trouble solving for the answer. I don't really understand the video.
