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the positive integers are arranged in the pattern illustrated below if this pattern continues indefinitely, what is the number immediately above 39863?

1  2 5 10 17 26

3  4 7 12 19 28

6  8 9 14 21 30

11 13 15 16 23 32

18 20 22 24 25 34

27 29 31 33 35 36

 

 

a) 39464  b)39861  c)39466  d)39468  e)39467 

 Dec 16, 2018

Best Answer 

 #6
avatar+20797 
+4

the positive integers are arranged in the pattern illustrated below if this pattern continues indefinitely, what is the number immediately above 39863?

1  2 5 10 17 26

3  4 7 12 19 28

6  8 9 14 21 30

11 13 15 16 23 32

18 20 22 24 25 34

27 29 31 33 35 36

 

Source: https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1131667.html

 

Let row = n

Let column = k

 

Formula:

\(\begin{array}{|rcll|} \hline T(n,k) &=& (k-1)^2+2n-1 \qquad & n\le k \\ T(n,k)&=&(n-1)^2+2k \qquad & n>k \\ \hline \end{array}\)

Source: http://oeis.org/search?q=a185725&sort=&language=english

 

1. \(\begin{array}{|rcll|} \hline \sqrt{39863} &=& 199.657\ldots \\ n_{min} &=& 199 \\ n_{max} &=& 200 \\ \hline \end{array}\)

 

 

\(\begin{array}{|rcll|} \hline T(200,k) &=& (200-1)^2+2k \qquad & n>k \\ 39863 &=& 199^2+2k \\ 2k &=& 39863 - 199^2 \\ 2k &=& 262 \\ \mathbf{k}& \mathbf{=}& \mathbf{131} \\ \hline \end{array} \)

 

The number immediately above:

\(\begin{array}{|rcll|} \hline T(199,131) &=& (199-1)^2+2\cdot 131 \qquad & n>k \\ T(199,131) &=& 198^2+2\cdot 131 \\ \mathbf{T(199,131)} & \mathbf{=}& \mathbf{39466} \\ \hline \end{array}\)

 

laugh

 Dec 17, 2018
 #1
avatar+812 
0

This pattern is a little difficult to understand because it is difficult to find a pattern.

 

We can restate the pattern to make it easier for us: 

 

1        2       5      10     17    26

3        4       7      12     18    28

6        8       9      14     21    30

11     13     15     16     23     32

18     20     22     24     25     34

27     29     31     33     35     36

 

On the first row, I see an additional change of 1, 3, 5, 7, and 9.

The second row has an additional change of 1, 3, 5, 6, and 10.

 

If we check the first column, the additional change is 2, 3, 5, 7, and 9.

 

Notice that the digit in the last column increases by 2 every column. 

 

The one directly above 39863 is C) 39466.

 

- PM

 Dec 17, 2018
 #2
avatar+812 
0

Check here.

PartialMathematician  Dec 17, 2018
 #3
avatar+812 
0

This one is a bogus solution.

PartialMathematician  Dec 17, 2018
 #4
avatar+812 
0

This solution is very good!

PartialMathematician  Dec 17, 2018
 #5
avatar+812 
0

another solution.

PartialMathematician  Dec 17, 2018
 #6
avatar+20797 
+4
Best Answer

the positive integers are arranged in the pattern illustrated below if this pattern continues indefinitely, what is the number immediately above 39863?

1  2 5 10 17 26

3  4 7 12 19 28

6  8 9 14 21 30

11 13 15 16 23 32

18 20 22 24 25 34

27 29 31 33 35 36

 

Source: https://www.algebra.com/algebra/homework/word/misc/Miscellaneous_Word_Problems.faq.question.1131667.html

 

Let row = n

Let column = k

 

Formula:

\(\begin{array}{|rcll|} \hline T(n,k) &=& (k-1)^2+2n-1 \qquad & n\le k \\ T(n,k)&=&(n-1)^2+2k \qquad & n>k \\ \hline \end{array}\)

Source: http://oeis.org/search?q=a185725&sort=&language=english

 

1. \(\begin{array}{|rcll|} \hline \sqrt{39863} &=& 199.657\ldots \\ n_{min} &=& 199 \\ n_{max} &=& 200 \\ \hline \end{array}\)

 

 

\(\begin{array}{|rcll|} \hline T(200,k) &=& (200-1)^2+2k \qquad & n>k \\ 39863 &=& 199^2+2k \\ 2k &=& 39863 - 199^2 \\ 2k &=& 262 \\ \mathbf{k}& \mathbf{=}& \mathbf{131} \\ \hline \end{array} \)

 

The number immediately above:

\(\begin{array}{|rcll|} \hline T(199,131) &=& (199-1)^2+2\cdot 131 \qquad & n>k \\ T(199,131) &=& 198^2+2\cdot 131 \\ \mathbf{T(199,131)} & \mathbf{=}& \mathbf{39466} \\ \hline \end{array}\)

 

laugh

heureka Dec 17, 2018

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