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A, B, C, and D are positive digits such that ABCD + BCD = 2012.  Find A + B + C + D.

 
 Jun 6, 2021

Best Answer 

 #1
avatar+174 
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D+D=12

D=6

C+C=10

C=5

If C=5, then 2B either equals 9 or 19. I don't know if you wrote the question right, since B either equals 4.5 or 19?

 

If you get rid of the "positive", and they are simply nonnegative, then it's possible: 

D=6

B=0

C=0

A=2

A+B+C+D=8

 

Correct me if I'm wrong though

 
 Jun 6, 2021
 #1
avatar+174 
+1
Best Answer

D+D=12

D=6

C+C=10

C=5

If C=5, then 2B either equals 9 or 19. I don't know if you wrote the question right, since B either equals 4.5 or 19?

 

If you get rid of the "positive", and they are simply nonnegative, then it's possible: 

D=6

B=0

C=0

A=2

A+B+C+D=8

 

Correct me if I'm wrong though

 
JKP1234567890 Jun 6, 2021

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