a landscape designer is drafting plans to landscape a community park, Inside the park is a rectangular garden with a perimeter of 94 feet. The area of the garden is 462 square feet. Where are the dimensions of the garden?
Let x and y be the length and width of the garden
x+y=94--1
x*y=462--2
from 1 , we have
x=94-y--3
Sub 3 into 2
(94-y)*y=462
94y-y^2-462=0
y=5.20287 or y=88.7971
so,x=88.7971 or x=5.20287
therefore the dimension are 88.7971 feet and 5.20287 feet.
a landscape designer is drafting plans to landscape a community park, Inside the park is a rectangular garden with a perimeter of 94 feet. The area of the garden is 462 square feet. Where are the dimensions of the garden?
Perimeter=2[L + W]
2[L + W]=94
Area=L X W
462=LW
L = 33 and W = 14 feet
