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Is there a way to divide a number by anything, like 2, a lot of times without doing this?

2048/2/2/2/2/2/2/2/2

 

Same with multiplication (Should work the same, right?)

 

This is easy, isn't it... Haha

 Feb 6, 2017

Best Answer 

 #4
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+5

Yes, that is correct haha

 Feb 6, 2017
 #1
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Yes, but it's a great question, so don't feel bad. :) The answer to your question is yes. 

I'm not sure about the multiplication part, you would need to give a number times a number, and see if it works or not. But 2048/2/2/2/2/2/2/2/2 =8. And the shortest way you can figure that out is to also do 2048/2^8. Your welcome :)

 Feb 6, 2017
 #2
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Oh, but that was an example. I was just wondering if there was an equation to shorten it.

 

Actually, this MIGHT work right?

(2048/2)8

Would that represent 2048/2/2/2/2/2/2/2/2 correctly?

 Feb 6, 2017
 #3
avatar+100 
+10

Solved it!

To shorten 2048 /2 /2 /2 /2 /2 /2 /2 /2

it would be 2048/2^8

 

Number/divideBy^#ofTimesToDivide

 Feb 6, 2017
 #4
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+5
Best Answer

Yes, that is correct haha

Guest Feb 6, 2017

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