+0  
 
0
46
1
avatar

What is the value of k such that (x^3−x^2+kx+40)÷(x + 5) has a remainder of zero? Then, factor the polynomial completely.

 Mar 5, 2021
 #1
avatar+31208 
+1

Long division

 

                  x^2 -6x +8

x+5 | x^3 -x^2 + kx + 40

        x^3 + 5x^2

              - 6x^2  + kx + 40

               -6x^2 -30x

                          (k+30)x + 40       k+ 30 must = 8 for this to have no remainder    so k = -22

                               8x     +40

 

 

(x+5)(x^2 -6x+8)

(x+5)(x-4)(x-2)   is factored

 Mar 5, 2021

49 Online Users

avatar
avatar
avatar
avatar