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Dmitri has a pair of standard dice; one die is blue, and the other die is yellow. He rolls both of his dice. How many ways could the number on the blue die be larger than or equal to the number on the yellow die?

 Nov 16, 2020

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Consider "tens digit" as blue die and the "ones digit" to be "yellow" die, then we have:

 

11 , 21 , 22 , 31 , 32 , 33 , 41 , 42 , 43 , 44 , 51 , 52 , 53 , 54 , 55 , 61 , 62 , 63 , 64 , 65 , 66 , Total =  21 ways

 

Or: Probability is: 21 / 6^2 =21 / 36 = 7 / 12

 Nov 16, 2020
 #1
avatar
+1
Best Answer

Consider "tens digit" as blue die and the "ones digit" to be "yellow" die, then we have:

 

11 , 21 , 22 , 31 , 32 , 33 , 41 , 42 , 43 , 44 , 51 , 52 , 53 , 54 , 55 , 61 , 62 , 63 , 64 , 65 , 66 , Total =  21 ways

 

Or: Probability is: 21 / 6^2 =21 / 36 = 7 / 12

Guest Nov 16, 2020

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