the sum of the squares of 3 positive, consecutive numbers is 149. Find the answer
the sum of the squares of 3 positive, consecutive numbers is 149. Find the answer
Yes I suppose it is a bit silly but some of us find questions like this fun :)
let the integers be
x-1, x and x+1
so their squares will be
\((x-1)^2,\;\; x^2\;\; and\;\; (x+1)^2\\ (x-1)^2+x^2+ (x+1)^2=149\\ x^2-2x+1\quad +x^2\quad +x^2+2x+1=149\\ x^2+1\quad +x^2\quad +x^2+1=149\\ 3x^2+2=149\\ 3x^2=147\\ x^2=49\\ x=7\)
So the numbers are 6,7 and 8
the sum of the squares of 3 positive, consecutive numbers is 149. Find the answer
Yes I suppose it is a bit silly but some of us find questions like this fun :)
let the integers be
x-1, x and x+1
so their squares will be
\((x-1)^2,\;\; x^2\;\; and\;\; (x+1)^2\\ (x-1)^2+x^2+ (x+1)^2=149\\ x^2-2x+1\quad +x^2\quad +x^2+2x+1=149\\ x^2+1\quad +x^2\quad +x^2+1=149\\ 3x^2+2=149\\ 3x^2=147\\ x^2=49\\ x=7\)
So the numbers are 6,7 and 8