How many grams of HCl will be produced with 16.2 grams of H2 and excess Cl2?
H2 + Cl2 -> 2HCl
Since you have excess Cl , the limiting factor is the H
16.2 gm of H2 is still 16.2 gm of H
Each 1.008 of hydrogen requires 35.45 gm of chlorine to form HCl
16.2 /1.008 x 35.45 = 569.732 gm Cl required
16.2 gm H + 569.732 gm of Cl = 585 .932 gm HCl
sii1lver, you have already asked this question. Two more explanations for this question are located at this link: https://web2.0calc.com/questions/i-also-need-help-on-questions-3-7-and-8-too-these#r5
Yes, the individual answers are not identical, but it is possible to attribute the small inaccuracy to rounding.