+0  
 
0
217
1
avatar+956 

If f(x) =1/(logx) and g(x) = 1/(8+x), what is the domain of (fxg)(x)? 

 

a) {x e R | x > 0 and x can't equal -8} 

b) {x e R | x > 0 and x can't equal 1} 

c) {x e R | x > 0} 

d{ {x e R | x can't equal -9 and 1} 

Julius  Jan 18, 2018

Best Answer 

 #1
avatar+7339 
+2

(f × g)(x)  =  ( 1 / (log x) )( 1 / (8 + x) )

 

Since  log x  is part of the function, we have the restriction  x > 0

 

Since  log x  is in a denominator, we have the restriction  log x  ≠  0

log x  ≠  0

x  ≠  100

x  ≠  1

 

Since  8 + x  is in a denominator, we have the restriction  8 + x  ≠  0

8 + x  ≠  0

x  ≠  -8               Notice that this is already accounted for with  x > 0

 

So the domain is all real  x  values such that  x > 0   and   x  ≠  1

hectictar  Jan 18, 2018
 #1
avatar+7339 
+2
Best Answer

(f × g)(x)  =  ( 1 / (log x) )( 1 / (8 + x) )

 

Since  log x  is part of the function, we have the restriction  x > 0

 

Since  log x  is in a denominator, we have the restriction  log x  ≠  0

log x  ≠  0

x  ≠  100

x  ≠  1

 

Since  8 + x  is in a denominator, we have the restriction  8 + x  ≠  0

8 + x  ≠  0

x  ≠  -8               Notice that this is already accounted for with  x > 0

 

So the domain is all real  x  values such that  x > 0   and   x  ≠  1

hectictar  Jan 18, 2018

43 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.