If h(x) is a function whose domain is [-8,8], and g(x)=h(2x^2), then the domain of g(x) is an interval of what width?
h(2x^2) means the g(x) function must fit within the -8 , 8 interval
domain of h only goes to 8
2x^2 = 8
x^2 = 4
x = +-2
when h goes to -8
2x^2 = -8
x^2 = -4
x= +- 2i not real
So I think the domain of g(x) is [-2,2] I have not seen anyone else answer these type of questions....I need to learn the correct answer too!