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If h(x) is a function whose domain is [-8,8], and g(x)=h(2x^2), then the domain of g(x) is an interval of what width?

 Jul 22, 2021
 #1
avatar+35247 
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    (not positive of this answer)

 Jul 22, 2021
edited by ElectricPavlov  Jul 22, 2021
 #2
avatar+35247 
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h(2x^2)    means the g(x) function must fit within the -8 , 8 interval

domain of h only goes to 8

2x^2 = 8

x^2 = 4

x = +-2                  

 

when h goes to -8

 

2x^2 = -8

x^2 = -4

x= +- 2i    not real

 

So I think the domain of g(x) is     [-2,2]       I have not seen anyone else answer these type of questions....I need to learn the correct answer too!

ElectricPavlov  Jul 22, 2021
edited by ElectricPavlov  Jul 22, 2021

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