Let p(x) = sqrt(-x), and q(x) = 8x^2 + 10x - 5. What is the domain of p(q(x))? Your answer will be of the form a <= x <= b. Find b - a.
p(q) must be negative ( less than or = 0 ) for sqrt(-x) to be a real number
p(q) is a bolw shaped parabola
8x^2 + 10x -5 <= 0
From the quadratic formula the zeroes are -5/8 +- sqrt (65)/8
everything between the zeroes will be negative values
-5/8-sqrt(65)/8 <= x <= -5/8 + sqrt(65)/8