Let p(x) = sqrt(-x) , and q(x) = 8x^2 + 10x - 2. What is the domain of p(q(x))? Your answer will be of the form a <= x <= b. Find b - a .
+36916 q(x) will have to be negative p(x) = sqrt(-x) to be REAL (rather than imaginary)
8x^2+10x-2 is a bowl shaped parabola
so the domain will be the x values between the roots of 8x^2+10x-2 (this will be the negative area of the parabola)
Use Quadratic Formula to compute the roots....
