\(15\sum n=1 (2n-1)\)
I got that all messed up but basically the 15 goes over the sum and n=1 goes below it and (2n-1) is on the right hand side.
I'm supposed to find the sum of the series but I can't really figure out how to do this...
If you mean \(\sum_{n=1}^{15}(2n-1)\) then the following should help:
Can you take it from here?
Yes that's exactly what I meant, I tried figuring it out with the help of YouTube videos and I ended up with https://snag.gy/qGM8Vn.jpg
Is that correct?
Yes. 225 is the correct result.
thank you so much!
