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\(15\sum n=1 (2n-1)\)

 

I got that all messed up but basically the 15 goes over the sum and n=1 goes below it and (2n-1) is on the right hand side.

 

I'm supposed to find the sum of the series but I can't really figure out how to do this...

 Mar 11, 2019
 #1
avatar+28159 
+3

If you mean  \(\sum_{n=1}^{15}(2n-1)\) then the following should help:

 

 

Can you take it from here?

 Mar 11, 2019
 #2
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Yes that's exactly what I meant, I tried figuring it out with the help of YouTube videos and I ended up with   https://snag.gy/qGM8Vn.jpg

 

Is that correct?

Guest Mar 11, 2019
 #3
avatar+28159 
0

Yes. 225 is the correct result.

Alan  Mar 11, 2019
 #4
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thank you so much!

Guest Mar 11, 2019

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