Chords WY and XZ of a circle are perpendicular. If XV = 4, WV = 3, and VZ = 9, then find YZ.
+128460 The products of associated chord segments in a circle are equal......so....
WV * VY = XV * VZ
3 * VY = 4 * 9
VY = 4 * 9 / 3
VY = 36 / 3
VY = 12
And since VY and VZ are at right angles, YZ is the hypotenuse of right triangle VYZ
So....YZ = sqrt (VZ^2 + VY^2 ) = sqrt ( 9^2 + 12^2) =
sqrt (81 + 144) = sqrt (225) = 15
