On a town map, the city hall is located at (0, 4), the fire station is located at (2, 4), and the high school is located at (0,0). Each unit on the grid has a length of 1 mile.
There is a road that goes straight from the fire station to the high school, but between the three buildings is open space. If the parks department wants to make a park out of the triangular space between the buildings, what will the area of the park be?
+128475 We have a right triangle with the hypotenuse being the distance between the high school and the fire station and the two legs the distances from the high school to city hall and the distance between city hall and the fire station
The last two distances are 4 miles and 2 miles
The area = product of the legs / 2 = (4)(2)/ 2 = 8/2 = 4 miles^2
Here's a graph : https://www.desmos.com/calculator/kku5xejv1n
