+137 find x when
$\sqrt{x+\!\sqrt{x+\!\sqrt{x+\!\sqrt{x+\cdots}}}}=9$
I think i should multiply by x, but then that would just give $x\sqrt{x+\!\sqrt{x+\!\sqrt{x+\!\sqrt{x+\cdots}}}}=9x.$ thoughts?
+129899 Note that the given expression = 9
Square both sides
x + given expression = 81
x + 9 = 81
x = 81 - 9 = 72
+137 THANK YOU SO MUCH!!!!!!!!!
I had no idea it was that simple... ELEGANT solution 
im thinking of another way...what if we say that the sqrt thingy is a variable...the things behind it are the same
P. S. an aops algebra 1(or another book) has a similar problem
also im bored theres no questions being post :/
