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# Easy System of Equations

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Mike sold caramel corn for \$10, buttered popcorn for \$8, and lightly buttered popcorn for \$7. At the end of the day, Mike had sold 400 items and made \$3,272. If he sold twice as many lightly buttered popcorn boxes as buttered popcorn, how many of each type of popcorn did he sell?

Apr 27, 2018

#1
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Let the number of buttered popcorn =P, then:

The number of lightly-buttered popcorn =2P

Let the number of caramel corn sold =C

P + 2P + C = 400

8P + 14P + 10C =3,272, solve for C, P

Using substitution, we get:

P = 91 - buttered popcorns sold

91 x 2 =182 - lightly-buttered popcorns sold

C = 127 - caramel popcorns sold.

Apr 27, 2018
edited by Guest  Apr 27, 2018

#1
+1

Let the number of buttered popcorn =P, then:

The number of lightly-buttered popcorn =2P

Let the number of caramel corn sold =C

P + 2P + C = 400

8P + 14P + 10C =3,272, solve for C, P

Using substitution, we get:

P = 91 - buttered popcorns sold

91 x 2 =182 - lightly-buttered popcorns sold

C = 127 - caramel popcorns sold.

Guest Apr 27, 2018
edited by Guest  Apr 27, 2018