Elimination by reciprocal

(6/7)(3-5n) ≥ (3/5)(1-9n)

Let's start by multiplying both sides by the common denominator of 7 and 5, i.e., 35.....this will clear the fractions

(35) (6/7)(3-5n) ≥ (35) (3/5)(1-9n)  =

30 (3 - 5n)  ≥  21 (1 - 9n)       simplify

90 - 150n ≥  21 - 189n      add  150n  to both sides, subtract 21 from both sides

69 ≥  - 39n       divide both sides by -39   and reverse the inequality sign

-69/39 ≤ n         reduce the fraction by dividing top/bottom by 3

-23/13 ≤  n    or     written another way, 

n ≥  -23 / 13

http://www.cymath.com/answer.php?q=6%2F7(3-5n)%20%E2%89%A5%203%2F5(1-9n)

thanks! appreciate it