First Question
9x - 9y = -99x - 9y = -9
9x - 9y = -99x - 9y = -9 (cancel -9y)
9x = -99x = -9 | ÷ -9
-x = 11x = 1 | + x
0 = 12x = 1+x
If 12x = 0, then x = 0 but 1+x = 1+0 = 1 so 0 = 0 = 1 is not true. Hence there are no solutions
Second Question
(-8x + 9y) = 11 + (- 8x + 9y) = 11 | -(- 8x + 9y) on all sides
0 = 11 + 0 = 11
0 = 11 = 11
0 ≠ 11
No solutions
First question:
9x - 9y = -99x - 9y = -9
That implies: x - y = -11x - y = -1
x - y = -11x - y
x = -11x
1 = -11
That means you can't divide by x because you get a strange result..... That means x = 0.
0 - y = -1, y = 1.
Therefore \(x = 0, y= 1\)
Second question:
-8x + 9y = 11 - 8x + 9y = 11
Only know that you cannot subtract a number which is not 0 and then get the same results......
Therefore no solution.