+73 Ellie is investigating potential relationships between one having a canine pet preference and a female gender. Assume a survey of 101 randomly selected persons revealed the following data:
The probability of selecting a person with a feline pet preference is 0.251.
If a person with a feline pet preference is chosen, the probability they have a male gender is 0.538 and if a person with a canine pet preference is chosen, the probability they have a female gender is 0.427
If you were to choose a person at random from the sample, determine the probability they have a canine pet preference or a female gender.
+129852 Here's my best attempt
Easiest way to do this is with a table....we will have to round a little so that we get whole numbers....
Canine Preference Feline Preference
Male ??? .538 *.251 * 101
Female .427 * ( 1-.251) * 101 ???
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(1-.251) * 101 .251 * 101
Filling in what we know and solving for what we don't.... we have
Canine Preference Feline Preference Total
Male ≈ 44 ≈ 14 ≈ 58
Female ≈ 32 ≈ 11 ≈ 43
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≈ 76 ≈ 25 101
P ( canine preference or female gender ) =
P ( canine) + P (female) - P ( canine and female) =
76/101 + 43/101 - 32/101 =
≈ 87 / 101
