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# Ellie is investigating potential relationships between one having a canine pet preference and a female gender.

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Ellie is investigating potential relationships between one having a canine pet preference and a female gender. Assume a survey of 101 randomly selected persons revealed the following data:

The probability of selecting a person with a feline pet preference is 0.251.

If a person with a feline pet preference is chosen, the probability they have a male gender is 0.538 and if a person with a canine pet preference is chosen, the probability they have a female gender is 0.427

If you were to choose a person at random from the sample, determine the probability they have a canine pet preference or a female gender.

Dec 22, 2020

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Again with the Venn diagram:

canine OR female =    (320 +116   + 135 )/1000 = .571

Dec 22, 2020
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*** edit ***

canine OR female =    (320 +116   + 429 )/1000 = .865

Guest Dec 22, 2020
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Here's my best attempt

Easiest way to do this is  with a  table....we will have to round a little  so that we get whole numbers....

Canine  Preference          Feline Preference

Male                 ???                              .538 *.251 * 101

Female       .427 * ( 1-.251) * 101             ???

_______________________________________

(1-.251) * 101                       .251 * 101

Filling in what we  know and  solving  for  what we don't.... we have

Canine Preference             Feline Preference             Total

Male                ≈  44                                      ≈  14                          ≈ 58

Female            ≈  32                                       ≈ 11                          ≈ 43

_________________________________________________

≈  76                                        ≈ 25                           101

P ( canine preference  or female gender )  =

P ( canine)  + P (female)  - P ( canine and female)  =

76/101  + 43/101  - 32/101  =

≈ 87 / 101

Dec 22, 2020