+37153 Before the ball is dropped it has POTENTIAL energy = mgh all of this energy is converted to kintetic energy 1/2 mv^2 at the point where the basketball hits the floor
(original) mgh = 1/2 mv^2(at floor) I cannot graph these equations here. g'luck !
+37153 For 'B' it is not a perfectly elastic collision between the ball and the concrete.... some of the energy is lost in making a sound (air vibrations) some of the enrgy is lost in vibrations in the concrete, some of the nergy is lost in deformation of the ball AND the concrete...even though they may spring back to the original shape, this deformation results in heat in the ball and the concrete, lastly , thee is AIR friction to which the ball loses energy...this results in a minute heating of th air and the ball.
+37153 Before the ball is dropped it has POTENTIAL energy = mgh all of this energy is converted to kintetic energy 1/2 mv^2 at the point where the basketball hits the floor
(original) mgh = 1/2 mv^2(at floor) I cannot graph these equations here. g'luck !
