Enter the correct probability in decimals in the probability distribution table.

Hev123  May 22, 2018

Hey Hev123!


I’m not familiar with this form of representing data, but I can try. 


If the right side is the amount of outcomes, one can draw this conjecture:


A total of 4 + 12 + 21 + 32 + 12 = 80 trials have been made. 


A total of 32 attempts have been satisfactory to be placed in the 4th row. 


Therefore the probability of another attempt being in the 4th row is:


32/80 = 0.4 = 2/5 = 40%


I hope this helped,



GYanggg  May 22, 2018

10 Online Users


New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.