Enter the correct probability in decimals in the probability distribution table.
I’m not familiar with this form of representing data, but I can try.
If the right side is the amount of outcomes, one can draw this conjecture:
A total of 4 + 12 + 21 + 32 + 12 = 80 trials have been made.
A total of 32 attempts have been satisfactory to be placed in the 4th row.
Therefore the probability of another attempt being in the 4th row is:
32/80 = 0.4 = 2/5 = 40%
I hope this helped,