Enter the correct probability in decimals in the probability distribution table.

Hey Hev123!

 

I’m not familiar with this form of representing data, but I can try. 

 

If the right side is the amount of outcomes, one can draw this conjecture:

 

A total of 4 + 12 + 21 + 32 + 12 = 80 trials have been made. 

 

A total of 32 attempts have been satisfactory to be placed in the 4th row. 

 

Therefore the probability of another attempt being in the 4th row is:

 

32/80 = 0.4 = 2/5 = 40%

 

I hope this helped,

 

Gavin