+0  
 
0
41
1
avatar+238 

Number of complex zeros for the polynomial function

 

f(x)=x^4+5x^2+6

KennedyPape  Oct 23, 2018

Best Answer 

 #1
avatar+2714 
+1

When you say complex, do you mean non-real?

 

This is a 4th degree polynomial.  There are clearly 4 complex zeros.

 

However it looks like some of them might be real.

 

\(x^4+5x^2+6 = (x^2+3)(x^2+2)\)

 

Nope.  None of these zeros are real.  So there are 4 complex zeros.

 

Given that factors can you quickly list off what they are?

Rom  Oct 23, 2018
 #1
avatar+2714 
+1
Best Answer

When you say complex, do you mean non-real?

 

This is a 4th degree polynomial.  There are clearly 4 complex zeros.

 

However it looks like some of them might be real.

 

\(x^4+5x^2+6 = (x^2+3)(x^2+2)\)

 

Nope.  None of these zeros are real.  So there are 4 complex zeros.

 

Given that factors can you quickly list off what they are?

Rom  Oct 23, 2018

17 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.