+0  
 
+1
187
2
avatar+1015 

Enter the number of complex zeros for the polynomial function in the box.

 

AngelRay  Feb 8, 2018
 #2
avatar+89909 
+1

Not as tricky as it seems....!!!

 

Note we can factor this as

 

x ( x^4   + 4x^2  - 5 )  

 

And the second polynomial can be factored as

 

x (x^2 + 5) (x^2 - 1)   =   

 

And we can continue

 

x ( x^2 + 5) (x + 1) ( x - 1)

 

We have thre real roots   x = 0, x = -1 and x  = 1

 

The  "x^2 + 5"  will produce two  complex roots

 

So.....2  is the number of complex roots (zeroes)

 

 

 

cool cool cool

CPhill  Feb 8, 2018
edited by CPhill  Feb 8, 2018

29 Online Users

avatar
avatar
avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.