+0  
 
+1
62
2
avatar+660 

Enter the number of complex zeros for the polynomial function in the box.

 

AngelRay  Feb 8, 2018
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1+0 Answers

 #2
avatar+82944 
+1

Not as tricky as it seems....!!!

 

Note we can factor this as

 

x ( x^4   + 4x^2  - 5 )  

 

And the second polynomial can be factored as

 

x (x^2 + 5) (x^2 - 1)   =   

 

And we can continue

 

x ( x^2 + 5) (x + 1) ( x - 1)

 

We have thre real roots   x = 0, x = -1 and x  = 1

 

The  "x^2 + 5"  will produce two  complex roots

 

So.....2  is the number of complex roots (zeroes)

 

 

 

cool cool cool

CPhill  Feb 8, 2018
edited by CPhill  Feb 8, 2018

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