Enter the number of complex zeros for the polynomial function in the box.

AngelRay Feb 8, 2018

#2**+1 **

Not as tricky as it seems....!!!

Note we can factor this as

x ( x^4 + 4x^2 - 5 )

And the second polynomial can be factored as

x (x^2 + 5) (x^2 - 1) =

And we can continue

x ( x^2 + 5) (x + 1) ( x - 1)

We have thre real roots x = 0, x = -1 and x = 1

The "x^2 + 5" will produce two complex roots

So.....2 is the number of complex roots (zeroes)

CPhill Feb 8, 2018