You purchase 5 tickets to a football game from an Internet agency. In addition to the cost per ticket, the agency charges a convinience charge of $2.50 per ticket. You choose to pay for rush delivery, which costs $15. The total cost of your order is $352.50. What is the price per ticket not including the convinience proce?
+118687 Sorry isi, this bit is incorrect
337.5 = 2.5(5x)
it should be
337.5=5(x+2.5)
$${\mathtt{337.5}} = {\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2.5}}\right) \Rightarrow {\mathtt{x}} = {\mathtt{65}}$$
the tickets are $65 each just like Geno3141 said.
I'll give you points for your good effort. 
+23252 Let the price of a ticket be x.
Since you bought 5 tickets, the total cost for all five tickets is 5x.
The convenience charge is 2.50 per ticket, and since there are 5 tickets, this will be 2.50·5.
To this you have to add 15 for ruh delivery.
Equation: 5x + 2.50·5 + 15.00 = 352.50
5x + 12.50 + 15.00 = 352.50
5x + 27.50 = 352.50
5x = 325.00
x = $65.00
+109 Let x = price per ticket
price w/o delvery cost
352.5 - 15 = 337.5
price per ticket with surcharge
337.5 = 2.5(5x)
337.5 = 12.5x
$27/ticket = x
then, all you do to get the cost without the surcharge is subtract the cost of the surcharge from the cost of one ticket:
27 - 2.5 = 24.5
therefore your final answer is: $24.50 per ticket without any surcharge.
+118687 Sorry isi, this bit is incorrect
337.5 = 2.5(5x)
it should be
337.5=5(x+2.5)
$${\mathtt{337.5}} = {\mathtt{5}}{\mathtt{\,\times\,}}\left({\mathtt{x}}{\mathtt{\,\small\textbf+\,}}{\mathtt{2.5}}\right) \Rightarrow {\mathtt{x}} = {\mathtt{65}}$$
the tickets are $65 each just like Geno3141 said.
I'll give you points for your good effort.
