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Find an equation for the perpendicular bisector of the line segment whose endpoints are (9,-3) and (-5,-7).

 Feb 28, 2021
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(9, -3) and (-5, -7)

 

midpoint: \((\frac{9-5}{2}, \frac{-3-7}{2}) = (2, -5)\)

 

slope: \(\frac{-7+3}{-5-9} = \frac{2}{7}\)

 

perpendicular bisector has a perpendicular slope and passes through the midpoint:

 

\(y+5 = \frac{2}{7}(x-2)\)

 Feb 28, 2021

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