Find an equation for the perpendicular bisector of the line segment whose endpoints are (9,-3) and (-5,-7).
(9, -3) and (-5, -7)
midpoint: \((\frac{9-5}{2}, \frac{-3-7}{2}) = (2, -5)\)
slope: \(\frac{-7+3}{-5-9} = \frac{2}{7}\)
perpendicular bisector has a perpendicular slope and passes through the midpoint:
\(y+5 = \frac{2}{7}(x-2)\)