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Find the equation of a line passing through (15,-7) perpendicular to the line 5x+6y=11

 Mar 10, 2021
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5x + 6y = 11 

6y = -5x + 11

y = 56x+116

 

Since the slope is 56 , the perpendicular slope to it is 65
 

y = mx + b  --> (15, -7)

7=65(15)+b

 7=18+b

b=25

 

This means the equation of this line is:
y=65x25

 Mar 10, 2021

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