Find the equation of a line passing through (15,-7) perpendicular to the line 5x+6y=11
5x + 6y = 11
6y = -5x + 11
y = −56x+116
Since the slope is −56 , the perpendicular slope to it is 65
y = mx + b --> (15, -7)
−7=65(15)+b
−7=18+b
b=−25
This means the equation of this line is:
y=65x−25