+817 Write the equation for the perpendicular bisector of the line segment connecting the points $(3,2)$ and $(-1,7)$ in the form $y = mx + b$.
Note: The perpendicular bisector of the line segment $\overline{AB}$ is the line that passes through the midpoint of AB and is perpendicular to AB.
+1537 To find the equation of the perpendicular bisector of the line segment connecting the points (3,2) and (-1,7), we first need to find the midpoint of the line segment and the slope of the line segment.
The midpoint of the line segment is:
((3 - 1)/2, (2 + 7)/2) = (1, 4.5)
The slope of the line segment is:
(7 - 2) / (-1 - 3) = -5/4
The perpendicular bisector of the line segment will have a negative reciprocal slope of -4/5 and will pass through the midpoint of the line segment, (1, 4.5).
Therefore, the equation of the perpendicular bisector of the line segment is:
y - 4.5 = -4/5 (x - 1)
5y - 22.5 = -4x + 4
5y = -4x + 26.5
y = -\frac{4}{5} x + \frac{26.5}{5}
or
y = -0.8x + 5.3
