Let f(4)=8 and f'(4)=6. Then the equation of the tangent line to the graph of y=f(x) at x=4 is _____________.
I have no idea how to even begin this question any help is appreciated
We have a point (4,8) ...... and the slope of the curve at that point = 6
So...the equation of the tangent line to that point will have the same slope as the curve at that point....and we have
y - 8 = 6(x - 4)
y - 8 = 6x - 24 add 8 to both sides
y = 6x - 16
Doh!
I wasn't thinking f(4)=8 is basically stating the point (4,8)..
it's too late at night >_> I need sleep.. haha, thanks CPhill